3x^2-50x+176=0

Solution for 3x^2-50x+176=0 equation:

3x^2-50x+176=0

a = 3; b = -50; c = +176;
Δ = b2-4ac
Δ = -502-4·3·176
Δ = 388
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{388}=\sqrt{4*97}=\sqrt{4}*\sqrt{97}=2\sqrt{97}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{97}}{2*3}=\frac{50-2\sqrt{97}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{97}}{2*3}=\frac{50+2\sqrt{97}}{6}
$